Questions Bank-MCQ-Statistics – Class IX

The mean age of 5 students of a class is 10 years. If one student is excluded from the class, the new mean age becomes 9 years. The age of student who is excluded from the class is :

The ratio between upper limit and lower limit of a class is 3 : 2. If the class mark is 15, then lower limit of the class-interval is :

For \(x = -1\), the mode of data \(x + 1, 0, x + 2, x + 3\) and \(x + 4\) is :

A cricket player has a mean score of 50 runs in the four innings. How many runs to be scored by the player in the fifth innings to raise the mean score by five ?

The mean of the prime factors of 24 is :

The mode of the following data 44, 40, 40, 41, 45, 43, 45, 40, 41 is :

If lower limit and upper limit of a class are in the ratio 3 : 5 and its class size is 6, then the class mark of this class is :

\(x + 8,\ x\) and \(x – 3\) are the frequencies of three numbers 5, 8 and 10 respectively. If their arithmetic mean is 6, then the value of \(x \) is :

The median of first six whole numbers is :

Two students scored following marks (out of 10 marks) in five different subjects :
Student I : 2, 3, 4, 5, 6
Student II : 3, 3, 3, 4, 8
Which student scored better ?

The mean of perimeters of two squares having sides \(x \) units and \(y \) units is :

The mean weight of 10 students in a class is 50 kg. If the sum of the weights of 9 students is 453 kg, the weight of 10th student is :

The mean of three numbers is 4. If two of the numbers are 1 and 2, then the third number is :

In the class intervals 10-20, 20-30, the number 20 is included in :

If each observation of a data is increased by 5, then their mean :

The class mark of the class 90-120 is :

The range of the data 25, 18, 20, 22, 16, 6, 17, 15, 12, 30, 32, 10, 19, 8, 11, 20 is :

The marks obtained by 17 students in a mathematics test (out of 100) are given below : 91, 82, 100, 100, 96, 65, 82, 76, 79, 90, 46, 64, 72, 68, 66, 48, 49. The range of the data is :

The median of the data 78, 56, 22, 34, 45, 54, 39, 68, 54, 84 is

Mode of the data 15, 14, 19, 20, 14, 15, 16, 14, 15, 18, 14, 19, 15, 17, 15 is :

The mean temperature of \(30 \) days was taken as \(15^oC \), but later it was found that temperature of one day was noted as \(16^oC \) instead of \(13^oC \). The correct mean is :

Numbers \(7,\ 8, 3x + 2, 5x – 4, 40, 41\) are given in ascending order. If the median of the data is \(15\), then the value of \(x \) is :

The mean marks obtained by 15 students in a class is 73. If the marks of each student are doubled, then the new mean marks is :

The median of first 49 whole numbers is :

The mean of class–marks of (20 – 30) and (30 – 40) is :

The mean of 15 numbers is 18 and the mean of 10 numbers is 13. The mean of all the 25 numbers is :

The sum of first n natural numbers is given by \(\dfrac{n(n+1)}{2} \). The mean of first 100 natural numbers is:

If the class marks in a frequency distribution are 19.5, 26.5, 33.5, 40.5, then the class corresponding to the class mark 33.5 is

The mean of 10 numbers is 55. If one number is excluded, their mean becomes 50, the excluded number is :

Class mark of a particular class is 6.5 and class size is 3, then class interval is :

The range of the data 25.7, 16.3, 2.8, 21.7, 24.3, 22.7, 24.9 is :