Choose the Correct options
0 of 31 Questions completed
Questions:
You have already completed the quiz before. Hence you can not start it again.
Quiz is loading…
You must sign in or sign up to start the quiz.
You must first complete the following:
0 of 31 Questions answered correctly
Your time:
Time has elapsed
You have reached 0 of 0 point(s), (0)
Earned Point(s): 0 of 0, (0)
0 Essay(s) Pending (Possible Point(s): 0)
Average score 

Your score 

Which of the following is a polynomial?
An expression of the form , where is called a polynomial in of degree .
The following figure shows the graph of y = p(x), where p(x) is a polynomial. p(x) has :
The graph cuts the axis at three points. So it has zeroes.
The following figure shows the graph of y = p(x), where p(x) is a polynomial. p(x) has :
The graph does not cut the axis at any point. So it has no zeroes.
If zeroes of the quadratic polynomial \(2x^28xm \) are \(\dfrac{5}{2} \) and \(\dfrac{3}{2} \) respectively, then the value of \(m \) is
If one zero of the quadratic polynomial \(2x^28xm \) is \(\dfrac{5}{2} \), then the other zero is:
If \(\alpha \) and \(\beta \) are zeroes of \(x^2+5x+8 \), then the value of \( \alpha+\beta\) is:
If \(\alpha \) and \(\beta \) are the zeroes of the quadratic polynomial \(f(x)=x^2x4 \), then the value of \(\dfrac{1}{\alpha}+\dfrac{1}{\beta}\alpha\beta \) is:
If \(\alpha \) and \(\beta \) are the zeroes of the quadratic polynomial \(f(x)=x^2p(x+1)c \), then \((\alpha+1)\ (\beta+1) \) is equal to :
If \(\alpha \) and \(\beta \) are the zeroes of the quadratic polynomial \(f(x)=x^25x+k \) such that \(\alpha\beta=1 \), then value of \(k \) is:
on solving
If \(\alpha \) and \(\beta \) are the zeroes of the polynomial \(f(x)=x^2p(x+1)c \) such that \((\alpha+1)\ (\beta+1)=0 \), then \(c \) is equal to
The value of \(k \) such that the quadratic polynomial \(x^2(k+6)+2(2k+1) \) has sum of the zeroes as half of their product is :
If \(\alpha \) and \(\beta \) are the zeroes of the polynomial \(p(x)=4x^25x1 \), then value of \(\alpha^2\beta+\alpha\beta^2 \) is:
If sum of the squares of zeroes of the quadratic polynomial \(f(x)=x^28x+k \) is \(40 \), the value of \( k\) is
The graph of the polynomial p(x) cuts the xaxis 5 times and touches it 3 times. The number of zeroes of p(x) is :
The number of zeroes
The zeroes of the quadratic polynomial \(x^2+89x+720 \) are:
If the zeroes of the quadratic polynomial \(ax^2+bx+c,c\ \ne\ 0 \), are equal, then :
and have the same sign
If one of the zeroes of a quadratic polynomial of the form \(x^2+ax+b \) is the negative of the other, then it :
It has no linear term and the constant term is negative.
A polynomial of degree 7 is divided by a polynomial of degree 4. Degree of the quotient is :
If a polynomial of degree 7 is divided by a polynomial of degree 4 then the degree of the quotient is 7 – 4 =3
The number of zeroes, the polynomial \(f(x)=(x3)^2+1 \) can have is :
Sum of zeroes = 6, Product of zeroes = 10
A polynomial of degree 7 is divided by a polynomial of degree 3. Degree of the remainder is :
The degree of the remainder can be 0, 1, 2
The graph of \(y = f(x)\), where \(f(x)\) is a quadratic polynomial meets the xaxis at \(A(2, 0)\) and \(B(3, 0)\), then the expression for \(f(x)\) is :
The graphs of \(y=f(x) \), where \(f(x) \) is a polynomial in \(x \) are given below. In which case \(f(x) \) is not a quadratic polynomial?
For any quadratic polynomial the graph has one of the two shapes either open upwards or open downwards.
The graph of \(y=f(x) \), where \(f(x) \) is a polynomial in \(x \) is given below. The number of zeroes lying between \(2 \) to \(0 \) of \(f(x) \) is:
Between 2 to 0 the graph cuts the xaxis at 2 points.
If \(\alpha \) and \(\beta \) are the zeroes of the polynomial \(5x^27x+2 \), then sum of their reciprocals is :
The graph of \(y=f(x) \) is shown. The number of zeroes of \(f(x) \) is:
The number of zeroes is 1 as it cuts at one point in xaxis.
If \(\alpha \) and \(\beta \) are the zeroes of the polynomial \(4x^2+3x+7 \), then \(\dfrac{1}{\alpha}+\dfrac{1}{\beta} \) is equal to:
The graph of \(y=p(x) \), where \(p(x) \) is a polynomial is shown. The number of zeroes of \(p(x) \) is:
The graph cuts at one point in xaxis. So the number of zeroes is 1.
If \(\alpha,\beta \) are zeroes of \(x^26x+k \), what is the value of \(k \) if \(3\alpha+2\beta=20 \)?
….(1)
…(2)
on solving we get
If one zero of \(2x^23x+k \) is reciprocal to the other, then the value of \(k \) is:
Let the two zeroes be and
The quadratic polynomial whose sum of zeroes is 3 and product of zeroes is –2 is :
– (Sum of zeroes) + product of zeroes
The quadratic polynomial \(p(y) \) with \(15 \) and \(7 \) as sum and one of the zeroes respectively is :
Let be
– (sum of zeroes) + product of zeroes