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The construction of a triangle \(ABC \), given that \(BC=6\ cm,\ \angle B=45^o \) is not possible when difference of \(AB \) and \(AC \) is equal to:
We know that construction of a triangle is not possible if sum of two sides is less than or equal to the third side
i.e.
If then construction of is not possible
The construction of a triangle \(ABC \), given that \(BC=3\ cm,\ \angle C=60^o \) is possible when difference of \(AB \) and \(AC \) is equal to
If then construction of is not possible
The construction of a triangle \(ABC \) in which \(AB=4\ cm,\ \angle A=60^o \) is not possible when difference of \(BC \) and \(AC \) is equal to
Which of the following angles cannot be constructed with the help of a ruler and a compass ?
can be constructed as all there are divisible by 15
To construct the perpendicular bisector of a line segment AB, we draw two equal arcs taking as centers A and B with radius :
We draw two equal arcs taking as centres A and B with radius more than
In the figure, \(\triangle \)ABC is constructed when its perimeter and two base angles are given. In this construction line segment XY is drawn equal to
A line segment XY is drawn equal to perimeter i.e. AB + BC + CA
With the help of a ruler and a compass, it is not possible to construct an angle of :
With the help of a ruler and a compass we can construct the angles etc. as there are divisible by . But it is not possible to construct as it is not divisible by
With the help of ruler and compass, it is not possible to construct an angle of :
As is not divisible by
With the help of a ruler and a compass, it is possible to construct an angle of :
As is divisible by