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If sum of two parallel sides of a trapezium is \(15\ cm \) and its area is \(30\ cm^2 \), then the height of the trapezium is :
Area (Sum of parallel sides) heights
The altitude of a parallelogram is twice the length of the base and its area if \(1250\ cm^2 \). The lengths of the base and the altitude respectively are :
Base = 25 cm, height = 50 cm
In the figure PQRS is a parallelogram PM \(\bot \) RS and RN \(\bot \) PS. If PQ = 12 cm, PM = 6 cm and RN = 8 cm, then the length of PS is equal to :
ABCD is a parallelogram one of whose diagonals is AC. Then, which of the following is true ?
(opposite sides of a parallelogram)
Triangles on the same base are equal
Two adjacent sides of a parallelogram are 24 cm and 18 cm. If the distance between the longer sides is 12 cm, then the distance between the shorter sides is :
Which of the following figures lies on the same base and between the same parallels ?
(ii) lies on the same base and between the parallels
The side of an equilateral triangle is 4 cm. Its area is
Area
The area of the parallelogram ABCD is :
Area of triangle
Area of parallelogram
In the figure, ABCD is a parallelogram and EFCD is a rectangle. Now which of the following is correct option ?
If the sum of the parallel sides of a trapezium is 7 cm and distance between them is 4 cm, then area of the trapezium is :
Area
ABCD is a quadrilateral whose diagonal AC divides it into two parts equal in area then ABCD :
If diagonal divides into two parts then it forms a triangle.
It may be kite
The median of a triangle divides it into two :
Median of a triangle is a line segment joining vertex to the mid point of the opposite side. Thus a median of a triangle divides it into two triangles of equal area.
If ABCD is a parallelogram, then which of the following is true ?
(opposite sides of parallelogram)
In the figure, PQRS and PQLM are parallelogram and X is any point on side side QL. The area of \(\triangle \)PMX is equal to :
Area of of
In the given figure, ABC is a triangle and AD is one of its medians. The ratio of the areas of triangles ABD and ACD respectively is :
( AD is the median)
So, ratio of areas of triangles and
If the base of an isosceles triangle is 8 cm and one of the equal sides measures 5 cm, then the area of the isosceles triangle is :
Base
Equal sides
Area
Area
In the figure, point D divide the side BC of \(\triangle \)ABC in the ratio p : q.The ratio between the ar (\(\triangle \)ABD) and ar (\(\triangle \)ADC) is
In the figure, ABCD is a trapezium in which AB  CD and its diagonals AC and BD intersect at O. Now ar (\( \triangle\)AOD) is equal to :
(on the)
In the figure, DE  BC. Then, which of the following relations is true ?
area of BDE = area of CDE
area of BDE = ADE + CDE
area of ABE = area of ADC
P and Q are any two points lying on the sides CD and AD respectively of a parallelogram ABCD. Now which of the two triangles have equal area ?
area of
area of
area of = area of
The area of the figure formed by joining the mid–points of the adjacent sides of a rhombus with diagonals 12 cm and 16 cm is :
Area of rhombus
Area of joining the mid point
If a triangle and a parallelogram are on the same base and between the same parallels, then the ratio of the area of the triangle to the area of parallelogram is :
area of = area of = area of
area of area of
= area of + area of
area of
area of
The mid point of the sides of a triangle ABC along with any one of the vertices as the fourth point makes a parallelogram whose are is equal to :
Ratio of area of triangle to the area of parallelogram = 1 : 2
ABCD is parallelogram and O is mid point of AB. If area of the parallelogram is 74 sq cm, then area of \( \triangle\)DOC is
Area of area of parallelogram
sq cm
\(AD \) is the median of a triangle \(ABC \). Area of triangle \(ADC=15\ cm^2 \), then \(ar\ (\triangle ABC) \) is:
area of = area of
In the figure, AB  DC. Which of the following is true about the figure ?
So area of = area of
(Triangles on the same base are equal)
A rectangle and a rhombus are on the same base and between the same parallels. Then the ratio of their areas is :
Since a rectangle and a rhombus are on the same base and between the same parallels, their areas are equal. So, the ratio is 1:1
ABCD is a trapezium with parallel sides AB = a cm, CD =b cm. E and F are the mid – points of non–parallel sides. The ratio of ar (ABFE) and ar (EFCD) is
Ratio
If \(E, F, G, H\) are respectively the mid points of the sides of a parallelogram \(ABCD\), and \(ar\ (EFGH) = 40\ cm^2\), then ar (parallelogram \(ABCD\)) is :
area of area
= area of
area of
In the figure, D is the midpoint of side BC of \(\triangle \)ABC . and E is the midpoint of AD. Then the area of \(\triangle \)ABE is :
In \(\triangle \)ABC, AD is median of \(\triangle \)ABC and BE is median of \(\triangle \)ABD. If ar (\(\triangle \)ABD) = \(15\ \text{cm}^2 \), then ar (\(\triangle \)ABC) is
area of area of
area of
In the figure, AB  DC, then the triangles that have equal area are :
Triangles with same base and between the same parallels are equal in area.
\( D\) and \(E \) are the points on the sides \(AB \) and \(AC \) respectively of triangle \(ABC \) such that \(DEBC \). If area of \(\triangle DBC=15\ cm^2 \), then area \(\triangle EBC \) is:
is base
If area of parallelogram \( ABCD\) is \(25\ cm^2 \) and on the same base \(CD \), a triangle \(BCD \) is given such that area of \(BCD=x\ cm^2 \), then the value of \(x \) is:
area of
In the figure, if parallelogram ABCD and rectangle ABEF are of equal area, then :
…(1)
…(2)
The length of the diagonal of the square is 10 cm. The area of the square is :
Area