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Three points A, B, C are said to be collinear, if :
Three points a,b,c are said to be collinear if they lie on the same straight line.
The point (–3, 5) lies in :
The point (3,5) lies in the second quadrant
The points A(0, –2), B(3, 1), C(0, 4) and D(–3, 1) are the vertices of a :
are the vertices of a
It is a square
S is a point on xaxis at a distance of 4 units from yaxis to its right. The coordinates of S are
xcoordinate will be 4
ycoordinate will be 0
S = (4,0)
The distance between the points P(0, y) and Q(x, 0) is given by :
Distance
The distance of the point P(2, 3) from the x–axis is :
The point is (2, 0)
Distance
The distance of the point P(–6, 8) from the origin is :
origin
Distance
If the distance between the point (2, –2) and (–1, x) is 5, one of the value of x is :
The distance between the points (0, 5) and (5, 0) is
The point on the x–axis which is equidistant from P(–2, 9) and Q(2, –5) is :
Point are (7, 0)
The distance between the points P(2, –3) and Q(2, 2) is :
If the points P(2, 3), Q(5, k) and R(6, 7) are collinear, then the value of k is :
Area
The points M(0, 6), N(–5, 3) and P(3, 1) are the vertices of a triangle, which is :
Two sides are equal so it is an isoscele triangle
A is a point on yaxis at a distance of 4 units from xaxis lying below xaxis. The coordinates of A are :
xaxis = – 4, yaxis = 0
coordinates = (4, 0)
The midpoint of the line segment joining the points A(–2, 8) and B(–6, –4) is :
The point which divides the line segment joining the points (7, –6) and (3, 4) in the ratio 1 : 2 internally lies in the :
It lies in 4th quadrant
If the point P(2, 1) lies on the line segment joining points A(4, 2) and B(8, 4), then :
If the points (k, 2k), (3k, 3k) and (3, 1) are collinear, then k is :
The points (0, 6), (–5, 3) and (3, 1) are the vertices of a triangle which is :
If \(P\left(\dfrac{a}{3},4\right) \) is the midpoint of the line segment joining the point Q(–6, 5) and R(–2, 3), then the value of a is :
The perpendicular bisector of the line segment joining the points A(1, 5) and B(4, 6) cuts the yaxis at :
Slope
Perpendicular bisector will pass through mid point
For yintercapt, x = 0, y = 13
The ratio in which (4, 5) divides the join of (2, 3) and (7, 8) is :
Let point P(x,y) divides (a,b) and (c,d)
The yaxis divides the join of P(–4, 2) and Q(8, 3) in the ratio :
Two vertices of \(\triangle \)PQR are P(–1, 4) and Q(5, 2) and its centroid is G(0, –3). The coordinates of R are:
The xaxis divides the join of A(2, –3) and B(5, 6) in the ratio :
A point A divides the join of X(5, –2) and Y(9, 6) in the ratio 3 : 1. The coordinates of A are :
If M (–1, 1) is the mid–point of the line segment joining P(–3, y) and Q(1, y + 4), then the value of y is
If (x, 2), (–3, –4) and (7, –5) are collinear, then x is equal to :
If the area of the triangle formed by the points (a, 2a), (–2, 6) and (3, 1) is 5 square units, then a is equal to :
If the distance between the points (4, p) and (1, 0) is 5, then the value of p is :