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A number consists of two digits whose sum is 8. If 18 is added to the number its digits are reversed. Find the number.
Let one is digit be
Ten is digit
Number
Number obtained by reversing the digit
A/Q
Number
Solve \(\dfrac{3x+5}{2x+7}=4\)
Solve \(0.16(5x2)=0.4x+7 \)
The length of the rectangle exceeds its breadth by \(3\ cm\). If the length and breadth are each increased by \(2\ cm\), than the area will be \(70\ cm^2\). More than that of the given rectangle. The length is
Let breadth be
length
Area
New length
New breadth
New area
A/Q
Length
Divide 36 into two parts in such a way that \(\dfrac{1}{5}\) of one part is equal to \(\dfrac{1}{7}\) of the other
Let one part = x
other part = (36 – x)
other part
In a isoscales triangle, the base angles are equal and the vertex angles is \(80^o\). The base angles is
The difference between the two numbers is 48. The ratio of the two numbers is 7 : 3. What are the two numbers?
The length of a rectangle is twice its breadth. If the perimeterr is 72 meter. The length is
Aorahan is 5 years younger than Rahul four years later, Rohan will be twice a old as Aorahan. The present age of Rahul is
Let Rahul’s percentage
Aorahan
A/Q
A number is divided into two parts such that one part is 10 more than the other. If the two parts are in the ratio 5 :3. The number is
The sum of two consecutive multiples of 5 is 55. The multiples are
Let the multiples
A/Q
The difference in the measures of two complementry angles is 12. The angles are
If \(\dfrac{3}{5}th\) of a number is 4 more than \(\dfrac{1}{2}\) of the number. The number is
The sum of the two numbers is 25 one of the numbers exceed the other by 9. The numbers are
A number is 12 more than the other. The numberr are if their sum is 48
A sum of Rs 2700 is to be given in the form of 63 prizes . if the prize is of either of Rs 100 or Rs 25. The number of prizes of each type are
Let x be the type of prize Rs. 100. So Rs. 25 type will be (63x)
So, 15 for Rs. 100 type prize and 48 Rs. 25 type prizes are present
Fifteen years from now Ravi’s age will be 4 times his current age. What is his current age?
The sum of three consecutive multiples of 8 is 888. The multiples are
Solve \( \dfrac{x+1}{4}=\dfrac{x2}{2}\)
Solve \(\dfrac{3x}{2}\dfrac{x}{3}=8\)