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\(\left( { – {\rm{ 26}}} \right){\rm{ }} + {\rm{ }}17{\rm{ }} – {\rm{ }}\left( { – {\rm{ 23}}} \right)\)is equal to
On subtracting − 2 from 0, we get
0 − (− 2) = 0 + 2 = 2
8 more than − 7 is
8 more than − 7 = (− 7) + 8 = 1
If x is greater than 4, then 4 − x =
We know that if a is negative integer, then a = − a
It is given that x is greater than 4 where 4 − x is negative
Hence, 4− x = − (4 − x) = − 4 + x = x − 4
8 + − 4 is equal to
We know that, − 4 = 4
Hence 8 + − 4 = 8 + 4 = 12
(− 46) + (− 24) is equal to
Sum of (– 6) and 14 is
6 + 14 = 14 – 6 = 8
The temperature on a certain morning is 10℃ at 5 a. m. If the temperature drops 2 degree at 6 a.m. and rises 5 degree at 8 a.m. and again drops 2 degree at 9 a.m. What is the temperature at 9 a.m.?
Temperature at 5 a.m. = 10℃
Temperature decreased at 6 a.m. = 2℃ = 2
Temperature raised at 8 a.m. = 5℃ = +5
Temperature decreased at 9 a.m. = 2℃ = 2
Final temperature at 9 a.m. = (10) + (2) + (+5) + (2)
= 10 – 2 + 5 – 2
= 14 + 5
= 9℃.
f * is an operation such that for two integers p and q, \(p{\rm{ }}*{\rm{ }}q{\rm{ }} = {\rm{ }}p{\rm{ }} + {\rm{ }}q{\rm{ + }}2\), then find: \(\left( { – {\rm{ }}5} \right){\rm{ }}*{\rm{ }}\left( { – {\rm{ }}6} \right)\)
Given that:
Ramesh thinks of an integer. He subtracts 25 from it and gets the result as – 9. What was the integer he thought of?
Let the integer be x
According to statement:
x25 = 9
x=9+25
x=16
If the product of two integers is 63 and one of them is − 9, then the other integers is
It is given that the product of two integers =63
One of them = − 9
Let the other integer be x
Then,
Hence, the other integers is 7
The largest number that divides 64 and 72 and leave the remainders 12 and 7 respectively, is
By subtracting 12 and 7 from 64 and 72
We get
64 − 12 = 52 and 72 − 7 = 65
So, the required number is the HCF of 52 and 65.
It can be written as
52 = 4 × 13 and 65 = 5 × 13
HCF of 52 and 65 = 13
Hence, the largest number that divides 64 and 72 and leave the remainders 12 and 7 respectively, is 13.
The sum of two integers is − 33. If one of them is 28, then the other is
Let the other integer be x
Then,
X+28 = – 33
X= 3328=61
The sum of two integers is − 56. If one of them is 40, then the other is
It is given that the sum of two integers = − 56
One of them = 40
Let the other integer be x
So,
X+40=56
X= 5640 = 96
Hence, the other number is − 96
Replace * by in (30) – (26) * 10 – (65)
(30) – (26) =30+26=4
10 – (65) =55
Hence,
(30) – (26) > 10 – (65)
1 – 2 + 3 – 4 + 5 – 6 + ……… + 15 – 16=?
It can be written as
1 – 2 + 3 – 4 + 5 – 6 + 7 – 8 + 9 – 10 + 11 – 12 + 13 – 14 + 15 – 16
We get
= – 1 – 1 – 1 – 1 – 1 – 1 – 1 – 1
By calculation
= – 8
Calculate the sum:
2 + (5) + 2 + (5) + …. if the number of terms is 10.
If the number of terms is 10
We get
2 + (5) + 2 + (5) + 2 + (5) + 2 + (5) + 2 + (5)
On further calculation
= 2 – 5 + 2 – 5 + 2 – 5 + 2 – 5 + 2 – 5 = 15
Evaluate the following:
– 10 – 14 + 32 – 26 – 28 + 7 + 19 – 18 – 8 + 33
– 10 – 14 + 32 – 26 – 28 + 7 + 19 – 18 – 8 + 33
We get
= (10+14+26+28+18+8) +(32+7+19+33)
=13
Sum of 433 and – 247 subtracted from – 284 is ___?
We know that the sum of 433 and – 247 is
433 – 247 = 186
Subtracting – 284 we get
186 – (284) = 186 + 284 = 470
The sum of two integers is 546. If one of the integers is – 322, determine the other.
It is given that
Sum of two integers = 546
One of the integers = – 322
Let the o0ther integer be x
So,
x + (322) = 546
x322=546
x = 546+322
x = 868
\(\left( { – 2} \right){\rm{ }} + {\rm{ }}\left( { – 204} \right){\rm{ }} + {\rm{ 1}}04{\rm{ }} + {\rm{ 5}}04{\rm{ }} + {\rm{ }}\left( { – 104} \right){\rm{ }} + {\rm{ 3}}\)
Subtract the first integer from the second: 2000, 202
2002, 202
So, by subtracting the first integer from the second
202 – 2002 = – 1800
Find an integer x such that, x + (6) = 0
x + (6) = 0
By adding 6 on both sides
x – 6+6 = 0+6
So, we get
x = 6
Write all integers whose absolute values are less than 2.
The integers whose absolute values are less than 2 are
– 1, 0, 1
Find the predecessor of 891
The predecessor of – 891 is
891 – 1 = – 892