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Express 48 kg 50 g as kilogram (kg) using decimals:
48 kg 50 g
We know that 1000 g = 1 kg
So, we get 1 g = kg
It can be written as
48 kg 50 g = 48 +
We get
48 kg 50 g = 48.050 kg
Write 0.04 as fraction in lowest form
0.04
It can be written as
= 0 + 0.04
We get
= 0 + 4 hundredths
On further calculation
= 0 +
So, we get
=
Express 14.005 kg without using decimals
14.005 kg
We know that 1 kg = 1000 g
So, we get 1 g = kg
It can be written as
14.005 kg = 14 +
On further calculation
14.005 kg = 14 +
We get
14.005 kg = kg
Convert each of the following sets of unlike decimals to like decimal: 5.3294, 53.29, 532.94
5.3294, 53.29, 532.94
In the given values we know that 5.3294 contains 4 digits after decimal point so we change 53.29 as 53.2900 and 532.94 as 532.9400
Hence, 5.3294, 53.2900 and 532.9400 are like decimals.
\(12\dfrac{1}{4}\)as decimals =?
It can be written as
= 12 +
In order to make denominator 100
Multiply and divide by 25
We get
On further calculation
So, we get
= 12.25
\(\dfrac{{21}}{{100}}\)as decimals =______
We know that = 0.21
Hence, the decimal is 0.21
Convert the following set of unlike decimals to like decimal:
7.8, 7.85
7.8, 7.85
In the given values we know that 7.85 contains 2 digits after decimal point so by changing 7.8 as 7.80
Hence, 7.80 and 7.85 are like decimals.
Add 18.03, 146.3, 0.829 and 5.324
18.030 + 146.300 + 0.829 + 5.324 = 170.483
137 + \(\dfrac{5}{{100}}\)can be written in decimals as ______
137 +
We know that
1 hundred, 3 tens, 7 ones and 5 hundredths
Hence, the decimal is 137.05.
27.076 + 0.55 + 0.004=?
27.076 + 0.550 + 0.004 = 27.630
Radhika’s mother gave her ₹ 20.50 and her father gave her ₹10.80, find the total amount given to Radhika by her parents.
Amount given by Radhika’s mother = ₹ 20.50
Amount given by Radhika’s father = ₹10.80
So, the total amount given by her parents = ₹ 20.50+ ₹10.80 = ₹31.3
Hence, the total amount given by her parents is ₹31.3
Write Five hundred twentyfive and forty hundredths. as decimals.
Five hundred twentyfive and forty hundredths
It can be written as
525 + = 525.40
Nasreen bought 4 m 20 cm cloth for her shirt and 2 m 4 cm cloth for skirt. Find the total cloth bought by her.
Cloth bought by Nasreen for shirt = 4 m 20 cm = 4.20 m
Cloth bought by Nasreen for skirt = 2 m 4 cm = 2.04 m
So, the total cloth bought by her = 4.20 + 2.04 = 6.24 m = 6 m 24 cm
Hence, the total cloth bought by her is 6 m 24 cm.
Between which two whole numbers on the number line 0.9 is?
0.9 is 9 units from 0 and 1 units from 1
Write 4.8 decimal as fractions and reduce the fraction to the lowest form.
It can be written as
= 4 + 8 tenths
On further calculation
= 4 +
We get
= 4() +
By further simplification
=
=
So, reducing to lowest form
=
The sum of two numbers is 180. If one of them is 90.01, find the other.
One of the numbers = 90.01
Sum of two numbers = 180
Consider x as the other number
It can be written as
90.01 + x = 180
On further calculation
x = 18090.01
By subtraction
x = 89.99
Hence, the other number is 89.99
Write 20 + 8 + \(\dfrac{5}{{10}}\)as decimals.
We know that 20 + 8 + =
2 tens, 8 ones and 5 tenths
Hence, the decimal is 28.5.
Ruby bought a watermelon weighing 4 kg 100 g. Out of this she gave 1 kg 750 g to her neighbor. What is the weight of the watermelon left with Ruby?
Weight of watermelon bought by Ruby = 4 kg 100 g = 4.100 kg
Weight of watermelon Ruby gave to neighbor = 1 kg 750 g = 1.750 kg
So, the weight of watermelon left with Ruby = Weight of watermelon bought by Ruby – Weight of watermelon Ruby gave to neighbor
We get,
Weight of watermelon left with Ruby = 4.100 – 1.750 = 2.35 kg.
Write six and two tenths as decimals:
six and two tenths
It can be written as
The sum of two numbers is 80. If one of them is 58.01, find the other.
One of the numbers = 58.01
Sum of two numbers = 80
Consider x as the other number
It can be written as
58.01 + x = 80
On further calculation
x = 80 – 58.01
By subtraction
x = 21.99
Hence, the other number is 21.99
Raju bought a book for ₹ 40.65. He gave ₹70 to the shopkeeper. How much money did he get back from the shopkeeper?
Cost of the book = ₹ 40.65
Amount given = ₹70
So, the balance retuned = 70 – 40.65=29.35₹
Hence, the shopkeeper returned back 29.35₹