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In triangle \(ABC \), if \(AB=BC \) and \(\angle B=70^o,\angle A \) will be:
For two triangles, if two angles and the included side of one triangle are equal to two angles and the included side of another triangle. Then the congruency rule is:
In ASA condition two angles and the included side are equal
A triangle in which two sides are equal is called:
In isosceles triangle any of the two sides are equal.
The angles opposite to equal sides of a triangle are:
If E and F are the midpoints of equal sides AB and AC of a triangle ABC. Then:
and are equal sides.
(Given)
(Common angle)
(Halves of equal sides)
(By SAS rule)
Hence, BF = CE (CPCT)
ABC is an isosceles triangle in which altitudes BE and CF are drawn to equal sides AC and AB respectively. Then:
(common arm)
(Right angles)
(Given)
Hence, BE = CF (by CPCT)
If ABC and DBC are two isosceles triangles on the same base BC. Then:
(Common arm)
(Sides of isosceles triangle)
(Sides of isosceles triangle)
So, .
(By CPCT)
If ABC is an equilateral triangle, then each angle equals to:
Equilateral triangle has all its sides equal and each angle measures 60Â°.
(All sides are equal)
Hence, (Opposite angles of equal sides)
Also, we know that,
If AD is an altitude of an isosceles triangle ABC in which AB = AC. Then:
In and ,
(Given)
(Common)
(By RHS congruence condition)
(By CPCT)
In a right triangle, the longest side is:
In triangle ABC, rightangled at B.
By angle sum property, we know:
Hence,
So, is the largest angle.
Therefore, the side (hypotenuse) opposite to largest angle will be longest one.
If one angle of a triangle is equal to half of the sum of the other two equal angles than the triangle is
Let one angle = x
Sum of remaining two angles
A/Q
G is the centroid of the equilateral triangle ABC. If AB = 6 cm then AG is equal to
The length of the sides of a triangle are x,y,z respectively. If \(x^2+y^2+z^2=xy+yz+xz \), then the triangle is
In the given figure, ABC is an isosceles triangle such that \(AB = AC\) and \(\angle B=30^o \) AD is the median to the base BC. Then \(\angle BAD= \)
An isosceles triangle ABC is right angled at B. D is a point inside the triangle ABC. P and Q are the point of the perpendiculers drawn from D on the side AB and AC respectively of \(\triangle ABC \). If \(AP=x\ cm, AQ=y\ cm \) and \(\angle BAD=15^o \). Then \(\sin75^o= \)?
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From