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Write the following statement in the form of an equation: The sum of three times x and 10 is 13.
Write the following statement in the form of an equation: If you subtract 3 from 6 times a number, you get 9
Write the following statement in the form of an equation: Taking away 5 from x gives 10
x – 5 = 10
Write the following statement in the form of an equation: Four times a number p is 8
4p = 8
Write the following statement in the form of an equation: Add 1 to three times n to get 7
3n + 1 = 7
Write the following statement in the form of an equation: The number b divided by 6 gives 5.
The solution of the equation y + 2 = 2 is
y + 2 = 2
y = – 2 – 2 = – 4
The solution of the equation 2s = 0 is
2s = 0
s = 0/2 = 0
The solution of the equation 3s + 6 = 0 is
3s + 6 = 0
3s = 6
s = 6/3 = – 2
The solution of the equation 10p = 10 is
10p = 10
p = 10/10 = 1
The solution of the equation 10p + 10 = 110 is
10p + 10 = 100
10p = 110 – 10 = 100
or, p = 100/10 = 10
The solution of the equation 12p – 11 = 13 is
12p – 11 = 13
12p = 13 + 11 = 24
or, p = 24/12 = 2
The solution of the equation 2 (m + 3) = 8
2(m+3) = 8
m + 3 = 8/2 = 4
or, m = 4 3 = 1
The solution of the equation – 2(x + 3) = 4 is
2(x+3) = 4
x + 3 = 4/2 = 2
or, m = 2 3 = 5
The solution of the equation 0 = 4 + 4(m + 1) is
0 = 4 + 4(m + 1)
or, 4(m + 1) = 4
or, m + 1 = 4/4 = 1
or, m = 1 1 = 2
The sum of ages of father and his son is 75 years. If the age of the son is 25 years. Find the age of the father.
Son’s age = 25 years
Let the father’s age be x years
x + 25 = 75
x = 75 – 25 = 50 years
Rahim’s father is three times as old as Rahim. If sum of their ages is 56 years. Find the age of father.
Let Rahim’s age = x years
Rahim’s father age = 3x years
x + 3x = 56
4x = 56
x = 14
The length of a rectangle is three times its width. If the perimeter of the rectangle is 96 metres, find the length of the rectangle.
Let width of rectangle = x
Length = 3x
Perimeter
Length
The sum of three consecutive natural numbers is 114. Find the numbers.
Let the consecutive numbers be x, x+ 1, x+2.
x + x+1 + x+2 = 114
3x + 3 = 114
x = 37
The numbers are 37, 38, 39.
Solve 3(x + 3) – 2(x – 1) = 5(x – 5).
3(x + 3) – 2(x – 1) = 5(x – 5)
3x + 9 – 2x + 2 = 5x – 25
4x = 36
x = 9