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Which one of the following instruments is not needed for the construction purposes?
Colored pens are not needed for the construction purpose.
Which of the following angles can be constructed using ruler and compass?
45° can be constructed using ruler and compass.
Which of the following angles can be constructed using ruler and compass?
90° can be constructed using ruler and compass.
Which of the following angles cannot be constructed using ruler and compass?
110° cannot be constructed using ruler and compass.
Which of the following angles cannot be constructed using ruler and compass?
140° cannot be constructed using ruler and compass.
To construct an angle of 45°, we
To construct an angle of 45°, we bisect a 90° angle.
To construct an angle of 30°, we
To construct an angle of 30°, we bisect a 60° angle.
To construct an angle of 15°, we
To construct an angle of 15°, we bisect a 30° angle.
Arrange the following steps of construction of 30° in correct order.
A. With O as centre and any radius, draw an arc CD with the help of compasses, cutting the ray OA at B.
B. Draw a ray OA.
C. Join OE and angle EOA is the required angle.
D. With B and C as centres, draw two arcs which intersect each other at E.
B – A – D – C is the correct order.
Arrange the following steps of construction of 60° in correct order.
A. With O as centre and any radius, draw an arc CD with the help of compasses, cutting the ray OA at D.
B. With centre D and same radius, draw an arc cutting the arc CD at Q.
C. Draw a ray OA.
D. Join OQ and angle QOA is the required angle.
C – A – B – D is the correct order.
Arrange the following steps of construction of 90° in correct order.
A. With O as centre and any radius, draw an arc, cutting OA at P.
B. Draw a ray OA.
C. With Q as centre and same radius, draw an arc cutting the arc drawn in step II at R.
D. With P as centre and same radius, draw an arc cutting the arc drawn in previous step at Q.
E. Join OB and angle BOA is the required 90° angle.
F. From Q and R and same radius, draw arcs which intersect at point B.
B – A – D – C – F – E is the correct order.
Arrange the following steps of construction of 120° in correct order.
A. With O as centre and any radius, draw an arc CD with the help of compasses, cutting the ray OA at D.
B. With centre Q and same radius, draw an arc cutting the arc drawn in Step II at R.
C. Join OR and angle ROA is the required angle.
D. Draw a ray OA.
E. With centre D and same radius, draw an arc cutting the arc CD at Q.
D – A – E – B – C is the correct order.
Arrange the following steps of construction of equilateral triangle in correct order.
A. With B as centre and the same radius, draw an arc cutting the arc XB at C.
B. Draw a ray AP with initial point A.
C. Join AC and BC to obtain the required triangle.
D. With A as centre and radius equal to the length of the side of the triangle, draw an arc XB, cutting the ray AP at B.
B – D – A – C is the correct order.
To construct a triangle, along with its base, we also need
Both A and B are required.
“Draw a line segment of length 4.4cm. Bisect it and measure the length of each part”
Arrange the following steps of constructions in correct order.
A. With Q as centre and the same radius as in previous step, draw arcs cutting the arcs drawn in previous step. Name these two points A and B respectively.
B. Draw a line PQ of 4.4cm using a scale.
C. Join points A and B. Let O be the point where AB meets PQ. Then, O bisects the line segment PQ.
D. With P as centre and radius more than half of PQ, draw arcs, one on each side of PQ.
E. Measure the length of PO and PQ using the ruler.
B – D – A – C – E is the correct order.
To construct a triangle, along with its perimeter, we also need
Two base angles are required along with the perimeter.
To construct a triangle, along with its base, we also need
Both B and C are required.
“Construct a triangle ABC in which AB = 4.4cm, BC + CA = 7cm and \(\angle B = 60^{\circ}\)”
Arrange the following steps of constructions in correct order.
A. Join AD
B. From ray BY, cut off line segment BD = BC + CA = 7cm.
C. Draw AB = 4.4cm
D. Draw an angle ABY = 60°.
E. Join AC to obtain the required triangle ABC.
F. Draw the perpendicular bisector of AD meeting BD at C.
C – D – B – A – F – E is the correct order.
“Construct a triangle PQR in which PQ = 3.5cm, QR + PR = 6.7cm and \(\angle Q = 40^{\circ}\)”
Arrange the following steps of constructions in correct order.
A. Draw PQ = 3.5cm
B. From ray QY, cut off line segment QE = QR + PR = 6.7cm.
C. Draw an angle PQY = 40°
D. Join PR to obtain the required triangle PQR.
E. Draw the perpendicular bisector of PE meeting QD at R.
F. Join PE.
A – C – B – F – E – D is the correct order.
“Construct a triangle ABC in which base BC = 5.7cm, AB – AC = 3cm and \(\angle B = 45^{\circ}\)”
Arrange the following steps of constructions in correct order.
A. Join CA to obtain the required triangle ABC
B. Join CD.
C. Draw an angle CBX = 45°
D. Draw base BC = 5.7cm.
E. Draw the perpendicular bisector of CD meeting BX at A.
F. From ray BX, cut off line segment BD = AB – AC = 3cm.
D – C – F – B – E – A is the correct order.
“Construct a triangle ABC in which base AB = 5cm, AC – BC = 2.5cm and \(\angle A = 30^{\circ}\)”
Arrange the following steps of constructions in correct order.
A. Draw base AB = 5cm
B. From ray AX, cut off line segment AD = AC – BC = 2.5cm.
C. Draw an angle BAX = 30°
D. Join BC to obtain the required triangle ABC.
E. Draw the perpendicular bisector of BD meeting AX at C.
F. Join BD.
A – C – B – F – E – D is the correct order.
“Construct a triangle ABC whose perimeter is equal to 14cm, \(\angle A = 45^{\circ}\) and \(\angle B = 60^{\circ}\)”
Arrange the following steps of constructions in correct order.
A. Draw the bisectors of angles \(\angle YXP [\latex] and [mathjax][latex]\angle XYQ [\latex]. Mark their point of intersection as C.
B. Join right bisectors of CX and CY. Mark their meeting point at XY as A and B respectively.
C. Join AC and BC to obtain the required triangle ABC.
D. Draw a line segment XY = 14cm.
E. Construct [mathjax][latex]\angle YXP = \angle A = 45^{\circ}\) and \(\angle XYQ = \angle Q = 60^{\circ}\) .
D – E – A – B – C is the correct order.